F(-8)=3x^2-5x+20

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Solution for F(-8)=3x^2-5x+20 equation: 



(-8)=3F^2-5F+20

We move all terms to the left:

(-8)-(3F^2-5F+20)=0

We add all the numbers together, and all the variables

-(3F^2-5F+20)-8=0

We get rid of parentheses

-3F^2+5F-20-8=0

We add all the numbers together, and all the variables

-3F^2+5F-28=0

a = -3; b = 5; c = -28;
Δ = b2-4ac
Δ = 52-4·(-3)·(-28)
Δ = -311
Delta is less than zero, so there is no solution for the equation

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